JAVA Exceptions
What will be the output?class MyClass{ public String test(){ try{ System.out.print("One"); return ""; } finally{ System.out.print("Two"); } }}public class Test{ public static void main(String args[]){ MyClass m = new MyClass(); m.test(); }}

Compilation Error
Two
One
One Two
None of these

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JAVA Exceptions
What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }}

None of these
Prints out: Exception
Compile with error
Prints out: Exception Finally
Prints out: Finally

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JAVA Exceptions
Given the code. What is the result when this program is executed?public class Test{ static int x[]; static{ x[0] = 1; } public static void main(String args[]){ }}

IllegalStateException is thrown
ExceptionInInitializerError is thrown
ArrayIndexOutOfBoundsException is thrown
StackOverflowException is thrown
None of these

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JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

This code will not compile, because in Java there are no pointers.
There is a NullPointerException. Everything went fine.
There is a NullPointerException.
There is a NullPointerException. There is an Exception.

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