JAVA Exceptions
Determine output of the following program code?public class Test{ public static void main(String args[]){ int i; try{ i = calculate(); System.out.println(i); }catch(Exception e){ System.out.println("Error occured"); } } static int calculate(){ return (7/2); }}

None of these
Compilation Error
3.5
3
Error occured

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JAVA Exceptions
What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }}

Compile with error
Prints out: Exception Finally
None of these
Prints out: Exception
Prints out: Finally

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"null pointer exception" is printed.
"one" is printed.
Compilation fails saying NullPointerException has already been caught.
None of these
"exception" is printed.

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