JAVA Exceptions
Determine output of the following program code?public class Test{ public static void main(String args[]){ int i; try{ i = calculate(); System.out.println(i); }catch(Exception e){ System.out.println("Error occured"); } } static int calculate(){ return (7/2); }}

Error occured
Compilation Error
3.5
None of these
3

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"null pointer exception" is printed.
"one" is printed.
None of these
"exception" is printed.
Compilation fails saying NullPointerException has already been caught.

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JAVA Exceptions
Given the code. What is the result when this program is executed?public class Test{ static int x[]; static{ x[0] = 1; } public static void main(String args[]){ }}

ArrayIndexOutOfBoundsException is thrown
ExceptionInInitializerError is thrown
StackOverflowException is thrown
IllegalStateException is thrown
None of these

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