JAVA Exceptions Which of the following blocks execute compulsorily whether exception is caught or not. throws throw finally catch throws throw finally catch ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }} Prints out: Exception Prints out: Finally Prints out: Exception Finally None of these Compile with error Prints out: Exception Prints out: Finally Prints out: Exception Finally None of these Compile with error ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }} Compilation fails-Exception NullPointerException is not compatible with throws clause in Name-B None of these Compilation succeed but no output Value-A printName() Compilation fails-Exception NullPointerException is not compatible with throws clause in Name-B None of these Compilation succeed but no output Value-A printName() ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What happen in case of multiple catch blocks? The superclass exception must be caught first. None of these Either super or subclass can be caught first. The superclass exception cannot caught first. The superclass exception must be caught first. None of these Either super or subclass can be caught first. The superclass exception cannot caught first. ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }} There is a NullPointerException. There is a NullPointerException. There is an Exception. There is a NullPointerException. Everything went fine. This code will not compile, because in Java there are no pointers. There is a NullPointerException. There is a NullPointerException. There is an Exception. There is a NullPointerException. Everything went fine. This code will not compile, because in Java there are no pointers. ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Exception generated in try block is caught in ........... block. throws catch finally throw throws catch finally throw ANSWER DOWNLOAD EXAMIANS APP