Process Equipment and Plant Design To avoid the tearing off the plate of an edge, the margin (i.e., the minimum distance from the centre of the rivet hole to the nearest edge of the plate) should be equal to 1.5 d 0.5 d D 2.5 d 1.5 d 0.5 d D 2.5 d ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The ratio of down take area to cross-sectional area of the tube, for calendria type evaporator ranges from 2 to 2.5 1.5 to 2 0.5 to 1 1 to 1.5 2 to 2.5 1.5 to 2 0.5 to 1 1 to 1.5 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design for couplings and unions would be 200 60 Negligible 350 200 60 Negligible 350 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Compensation against openings in process vessels for giving inlet and outlet connections, for providing sight glasses and manholes etc. is provided for strength and rigidity. The most efficient type of compensation is of __________ type. Fluid in Ring plate Nozzle or rim Flared out Fluid in Ring plate Nozzle or rim Flared out ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design The LMTD correction factor (FT) is defined as the Ratio of LMTD to the true temperature difference Geometric mean of the true temperature difference and the LMTD Ratio of true temperature difference to the LMTD Differenced of true temperature difference and the LMTD Ratio of LMTD to the true temperature difference Geometric mean of the true temperature difference and the LMTD Ratio of true temperature difference to the LMTD Differenced of true temperature difference and the LMTD ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For turbulent flow (NRe > 2100) of low viscosity fluid (μ > 20cp) in steel pipes, the optimum inside pipe diameter is given by(where, Q = fluid flow rate, ft³/sec.ρ = fluid density, lb/ft³ μ = fluid viscosity, centipoise Di = optimum inside pipe diameter, inches) Di, opt = 4.7 Q0.36 . μ3.2ρ0.13 Di, opt = 3.9 Q0.45 ρ0.13 Di, opt = 3.9 Q0.45 . μ0.95 Di, opt = 3 Q0.36 . μ0.88 Di, opt = 4.7 Q0.36 . μ3.2ρ0.13 Di, opt = 3.9 Q0.45 ρ0.13 Di, opt = 3.9 Q0.45 . μ0.95 Di, opt = 3 Q0.36 . μ0.88 ANSWER DOWNLOAD EXAMIANS APP
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