Hydraulics and Fluid Mechanics in ME The total energy of a liquid particle in motion is equal to Pressure energy - (kinetic energy + potential energy) Potential energy - (pressure energy + kinetic energy Kinetic energy - (pressure energy + potential energy) Pressure energy + kinetic energy + potential energy Pressure energy - (kinetic energy + potential energy) Potential energy - (pressure energy + kinetic energy Kinetic energy - (pressure energy + potential energy) Pressure energy + kinetic energy + potential energy ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME If velocity is zero over l/3rd of a cross-section and is uniform over remaining 2/3rd of the cross-section, then the correction factor for kinetic energy is 43892 27/8 44078 43924 43892 27/8 44078 43924 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A liquid compressed in cylinder has a volume of 0.04 m3 at 50 kg/cm² and a volume of 0.039 m3 at 150 kg/cm². The bulk modulus of elasticity of liquid is 40 × 10⁵ kg/cm² 400 kg/cm² 40 × 10⁶ kg/cm² 4000 kg/cm² 40 × 10⁵ kg/cm² 400 kg/cm² 40 × 10⁶ kg/cm² 4000 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Any change in load is adjusted by adjusting following parameter on turbine Flow Blade velocity Net head Absolute velocity Flow Blade velocity Net head Absolute velocity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The depth of centre of pressure (h) for a vertically immersed surface from the liquid surface is given by (where IG = Moment of inertia of the immersed surface about horizontal axis through its centre of gravity, A = Area of immersed surface, and x = Depth of centre of gravity of the immersed surface from the liquid surface) (Ax̅/IG) + x̅ (IG/Ax̅) + x̅ (IG/Ax̅) - x̅ (IG/x̅) - Ax̅ (Ax̅/IG) + x̅ (IG/Ax̅) + x̅ (IG/Ax̅) - x̅ (IG/x̅) - Ax̅ ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The error in discharge (dQ/Q) to the error in measurement of head (dH/H) over a triangular notch is given by dQ/Q = 3 × (dH/H) dQ/Q = 5/2 × (dH/H) dQ/Q = 3/2 × (dH/H) dQ/Q = 2 × (dH/H) dQ/Q = 3 × (dH/H) dQ/Q = 5/2 × (dH/H) dQ/Q = 3/2 × (dH/H) dQ/Q = 2 × (dH/H) ANSWER DOWNLOAD EXAMIANS APP
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