Applied Mechanics and Graphic Statics The torque produced by a force depends oni. the magnitude of the forceii. the direction of the forceiii. the point of application of the force relative to originThe correct answer is both (i) and (ii) all (i), (ii) and (iii) only (i) both (i) and (iii) both (i) and (ii) all (i), (ii) and (iii) only (i) both (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Time period and length of a second’s pendulum respectively are 2 sec and 92.7 cm 1 sec and 92.7 cm 1 sec and 99.4 cm 2 sec and 99.4 cm 2 sec and 92.7 cm 1 sec and 92.7 cm 1 sec and 99.4 cm 2 sec and 99.4 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The instantaneous centre of a member lies at the point of intersection of two lines drawn at the ends of the member such that the lines are inclined to the direction of motion of the ends at 45° 60° 90° 30° 45° 60° 90° 30° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of a homogeneous body is the point at which the whole Weight of the body is assumed to be concentrated Area of the surface of the body is assumed to be concentrated Volume of the body is assumed to be concentrated All listed here Weight of the body is assumed to be concentrated Area of the surface of the body is assumed to be concentrated Volume of the body is assumed to be concentrated All listed here ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A point subjected to a number of forces will be in equilibrium, if Algebraic sum of the forces is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the moments of the forces about the point is zero Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the forces is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the moments of the forces about the point is zero Sum of resolved parts in any two directions at right angles, are both zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 2gh v = √(2gh) v = 1/√(2gh) v = 2gh² v = 2gh v = √(2gh) v = 1/√(2gh) v = 2gh² ANSWER DOWNLOAD EXAMIANS APP
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