Applied Mechanics and Graphic Statics A ball is dropped from a height of 2.25 m on a smooth floor and rises to a height of 1.00 m after the bounce. The coefficient of restitution between the ball and the floor is 0.67 0.33 0.57 0.44 0.67 0.33 0.57 0.44 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The following factor affects the orbit of a satellite up to an altitude of 720 km from the earth's surface Gravity of the sun and the moon Uneven distribution of the gravitational field Aerodynamic forces None of these Gravity of the sun and the moon Uneven distribution of the gravitational field Aerodynamic forces None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A heavy ladder resting on a floor and against a vertical wall may not be in equilibrium, if Floor is rough and the wall is smooth Floor is smooth and the wall is rough Floor and wall both are smooth surfaces Floor and wall both are rough surfaces Floor is rough and the wall is smooth Floor is smooth and the wall is rough Floor and wall both are smooth surfaces Floor and wall both are rough surfaces ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(y² - r²) v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(y² - r²) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two balls of masses 3 kg and 6 kg are moving with velocities of 4 m/sec and 1 m/sec respectively, towards each other along the line of their centers. After impact the 3 kg ball comes to rest. This can happen only if the coefficient of restitution between the balls is 43835 43895 43833 43864 43835 43895 43833 43864 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π + 0.25)]/(π + 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π - 0.5) ANSWER DOWNLOAD EXAMIANS APP
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