Applied Mechanics and Graphic Statics The resolved part of the resultant of two forces inclined at an angle θ in a given direction is Difference of the forces multiplied by cosine θ° Arithmetical sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Algebraic sum of the resolved parts of the forces in the direction Difference of the forces multiplied by cosine θ° Arithmetical sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Algebraic sum of the resolved parts of the forces in the direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If A is the amplitude of particle executing simple harmonic motion, then the total energy E of the particle is Proportional to A² Independent of A Proportional to A Proportional to 1/A² Proportional to A² Independent of A Proportional to A Proportional to 1/A² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If ‘l’ is the span of a light suspension bridge who’s each cable carries total weight (w) and the central dip is ‘y’, the horizontal pull at each support, is wl/4y wl/2y wl/8y wl wl/4y wl/2y wl/8y wl ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The total kinetic energy of a hoop of mass 2 kg and radius 4 m sliding with linear velocity 8 m/sec and angular velocity 5 radian/sec is 89 J 64 J 464 J 400 J 89 J 64 J 464 J 400 J ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The motion of a particle is described by the relation x = t²- 10t + 30, where x is in meters and t in seconds. The total distance travelled by the particle from t = 0 to t = 10 seconds would be Zero 60 m 30 m 50 m Zero 60 m 30 m 50 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then, P = Q Q = R None of these P = R P = Q Q = R None of these P = R ANSWER DOWNLOAD EXAMIANS APP
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