Applied Mechanics and Graphic Statics The resolved part of the resultant of two forces inclined at an angle θ in a given direction is Difference of the forces multiplied by cosine θ° Algebraic sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Arithmetical sum of the resolved parts of the forces in the direction Difference of the forces multiplied by cosine θ° Algebraic sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Arithmetical sum of the resolved parts of the forces in the direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A satellite goes on moving along its orbit round the earth due to None of these Centripetal force Gravitational force Centrifugal force None of these Centripetal force Gravitational force Centrifugal force ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body of weight ‘w’ placed on an inclined plane is acted upon by a force ‘P’ parallel to the plane which causes the body just to move up the plane. If the angle of inclination of the plane is ‘θ’ and angle of friction is ‘φ’, the minimum value of ‘P’, is w sin (θ - φ)/cos φ w sin (φ - θ)/cos φ w sinθ cos(θ - φ)/sin φ w cos (θ + φ)/cos φ w sin (θ - φ)/cos φ w sin (φ - θ)/cos φ w sinθ cos(θ - φ)/sin φ w cos (θ + φ)/cos φ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle is dropped from a height of 3 m on a horizontal floor, which has a coefficient of restitution with the ball of 1/2. The height to which the ball will rebound after striking the floor is 1.0 m 0.75 m 1.5 m 0.5 m 1.0 m 0.75 m 1.5 m 0.5 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A trolley wire weighs 1 kg per metre length. The ends of the wire are attached to two poles 20 m apart. If the horizontal tension is 1000 kg, the central dip of the cable is 2 cm 4 cm 3 cm 5 cm 2 cm 4 cm 3 cm 5 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ tan θ P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ tan θ ANSWER DOWNLOAD EXAMIANS APP
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