Applied Mechanics and Graphic Statics The torque produced by a force depends on (i) The magnitude of the force (ii) The direction of the force (iii) The point of application of the force relative to origin Both (i) and (ii) All (i), (ii) and (iii) Only (i) Both (i) and (iii) Both (i) and (ii) All (i), (ii) and (iii) Only (i) Both (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics To attain the synchronous orbit, the launch of a satellite, is done from a place On 30° latitude On 45° latitude On the poles On equator On 30° latitude On 45° latitude On the poles On equator ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2PQ cos θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2P sin θ P² + Q² + 2PQ tan θ P² + Q² + 2PQ cos θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2P sin θ P² + Q² + 2PQ tan θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body slides down an inclined surface, the acceleration (f) of the body, is given by f = g f = g sin θ f = g cos θ f = g tan θ f = g f = g sin θ f = g cos θ f = g tan θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The member which does not carry zero force in the structure shown in below figure, is Applied Mechanics and Graphic Statics mcq question image BC ED DC BD BC ED DC BD ANSWER DOWNLOAD EXAMIANS APP
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