Applied Mechanics and Graphic Statics The rate of change of displacement of a body with respect to its surrounding, is known Acceleration Velocity None of these Speed Acceleration Velocity None of these Speed ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 3t² + 2t 3t³ - 2t 6t - 2 6t + 2 3t² + 2t 3t³ - 2t 6t - 2 6t + 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The moment of inertia of a triangular section (base b, height h) about centroidal axis parallel to the base, is bh³/3 bh³/36 bh³/2 b³h/12 bh³/3 bh³/36 bh³/2 b³h/12 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A system of coplanar forces is in equilibrium when Force polygon closes Funicular polygon closes All the forces are concurrent Both force polygon" and funicular polygon close Force polygon closes Funicular polygon closes All the forces are concurrent Both force polygon" and funicular polygon close ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh ANSWER DOWNLOAD EXAMIANS APP
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