Applied Mechanics and Graphic Statics The rate of change of displacement of a body with respect to its surrounding, is known Velocity None of these Acceleration Speed Velocity None of these Acceleration Speed ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Minimum pull in a suspended cable with supports at two ends is equal to Support reactions Half the weight of the cable Resultant of horizontal thrust and support reaction Horizontal thrust Support reactions Half the weight of the cable Resultant of horizontal thrust and support reaction Horizontal thrust ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A retarding force on a body does not Introduce the motion of the body Retard the motion of the body None of these Change the motion of the body Introduce the motion of the body Retard the motion of the body None of these Change the motion of the body ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics On a ladder resisting on a smooth ground and leaning against a rough vertical wall, the force of friction acts Away from the wall at its upper end Towards the wall at its upper end Downwards at its upper end Upwards at its upper end Away from the wall at its upper end Towards the wall at its upper end Downwards at its upper end Upwards at its upper end ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the velocity of projection is 4 m/sec and the angle of projection is α°, the maximum height of the projectile from a horizontal plane, is u² cos² α/2g u² tan² α/2g u² sin² α/2g u² sin 2α/2g u² cos² α/2g u² tan² α/2g u² sin² α/2g u² sin 2α/2g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π + 0.25)]/(π + 0.5) [r (π + 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π - 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π + 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π - 0.25)]/(π - 0.5) ANSWER DOWNLOAD EXAMIANS APP
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