Applied Mechanics and Graphic Statics The ratio of the speed of a rolling cylinder to the speed of sliding cylinder is Equal to 1 Between 1 and 2 Greater than 2 Less than 1 Equal to 1 Between 1 and 2 Greater than 2 Less than 1 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A string of length 90 cm is fastened to two points ‘A’ and ‘B’ at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force ‘P’ is applied to the ring such that it is in equilibrium vertically below ‘B’. The value of ‘P’ is: 60 g 100 g 80 g 40 g 60 g 100 g 80 g 40 g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angle of friction is: The force of friction at which the body is just about to move The angle between the normal reaction and the resultant of normal reaction and limiting friction The force of friction when the body is in motion The ratio of the friction and the normal reaction The force of friction at which the body is just about to move The angle between the normal reaction and the resultant of normal reaction and limiting friction The force of friction when the body is in motion The ratio of the friction and the normal reaction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² - y²) v = ω √(r² + y²) v = ω √(y² - r²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(r² + y²) v = ω √(y² - r²) y = ω √(y - r) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The forces which meet at one point and have their lines of action in different planes are called Intersecting forces Coplanar non-concurrent forces Non-coplanar non-current forces Non-coplanar concurrent forces Intersecting forces Coplanar non-concurrent forces Non-coplanar non-current forces Non-coplanar concurrent forces ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² ANSWER DOWNLOAD EXAMIANS APP
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