Applied Mechanics and Graphic Statics
A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is

100 kg
60 kg
10 kg
40 kg

ANSWER DOWNLOAD EXAMIANS APP

Applied Mechanics and Graphic Statics
‘ω’ rad/sec is the angular velocity of a crank whose radius is ‘r’. If it makes θ° with inner dead centre and obliquity of the connecting rod ‘l’ is ‘ϕ’, the velocity v of the piston, is given by the equation

ω² (l cos ϕ + r sin ϕ tan θ)
ω² (l sin ϕ - r cos θ tan ϕ)
ω² (l sin ϕ + r cos φ tan θ)
ω (l sin ϕ + r cos ϕ tan θ)

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Applied Mechanics and Graphic Statics