Applied Mechanics and Graphic Statics
A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is

100 kg
10 kg
60 kg
40 kg

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Applied Mechanics and Graphic Statics
When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by

g(M1 - M2 sin α)/(M1 + M2­) m/sec²
g(M2 + M1 sin α)/(M1 + M2­) m/sec²
g(M1 + M2 sin α)/(M1 + M2­) m/sec
g(M2 × M1 sin α)/(M2 - M1­) m/sec²

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