Applied Mechanics and Graphic Statics Centre of gravity of a thin hollow cone lies on the axis of symmetry at a height of One-fourth of the total height above base One-third of the total height above base None of these One-half of the total height above base One-fourth of the total height above base One-third of the total height above base None of these One-half of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Power developed by a torque, is 2πNT /60 watts All listed here 2πNT kg m/min 2πNT/4500 h.p 2πNT /60 watts All listed here 2πNT kg m/min 2πNT/4500 h.p ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Instantaneous center is at infinity when the angular velocity is Maximum Zero Constant Minimum Maximum Zero Constant Minimum ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Free body diagram is an Isolated joint with only body forces acting on it None of these Isolated joint with all the forces, internal as well as external, acting on it Isolated joint with internal forces acting on it Isolated joint with only body forces acting on it None of these Isolated joint with all the forces, internal as well as external, acting on it Isolated joint with internal forces acting on it ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Equation of motion of a point in a straight line, is S = ut + ½ ft² All listed here v = u + ft 2fS = v² - u² S = ut + ½ ft² All listed here v = u + ft 2fS = v² - u² ANSWER DOWNLOAD EXAMIANS APP
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