Applied Mechanics and Graphic Statics A point subjected to a number of forces will be in equilibrium, if Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the forces is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the moments of the forces about the point is zero Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the forces is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the moments of the forces about the point is zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The point about which combined motion of rotation and translation of a rigid body takes place, is known as Instantaneous axis Virtual centre Point of rotation Instantaneous centre Instantaneous axis Virtual centre Point of rotation Instantaneous centre ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle is dropped from the top of a tower 60 m high and another is projected upwards from the foot of the tower to meet the first particle at a height of 15.9 m. The velocity of projection of the second particle is 18 m/sec 16 m/sec 20 m/sec 22 m/sec 18 m/sec 16 m/sec 20 m/sec 22 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The Centre of gravity of a 10 × 15 × 5 cm T section from its bottom, is 8.75 cm 7.85 cm 7.5 cm 5.0 cm 8.75 cm 7.85 cm 7.5 cm 5.0 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A shell travelling with a horizontal velocity of 100 m/sec explodes and splits into two parts, one of mass 10 kg and the other of 15 kg. The 15 kg mass drops vertically downward with initial velocity of 100 m/sec and the 10 kg mass begins to travel at an angle to the horizontal of tan”1 x, where x is 4/5 3/5 5/3 3/4 4/5 3/5 5/3 3/4 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 1/√(2gh) v = 2gh² v = 2gh v = √(2gh) v = 1/√(2gh) v = 2gh² v = 2gh v = √(2gh) ANSWER DOWNLOAD EXAMIANS APP
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