Applied Mechanics and Graphic Statics Effect of a force on a body depends upon its All of these Direction Magnitude Position All of these Direction Magnitude Position ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Newton's law of Collision of elastic bodies states that when two moving bodies collide each other, their velocity of separation Is inversely proportional to their velocity of approach Is equal to the sum of their velocities of approach Bears a constant ratio to their velocity of approach Is directly proportional to their velocity of approach Is inversely proportional to their velocity of approach Is equal to the sum of their velocities of approach Bears a constant ratio to their velocity of approach Is directly proportional to their velocity of approach ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Time period and length of a second’s pendulum respectively are 2 sec and 99.4 cm 1 sec and 99.4 cm 1 sec and 92.7 cm 2 sec and 92.7 cm 2 sec and 99.4 cm 1 sec and 99.4 cm 1 sec and 92.7 cm 2 sec and 92.7 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The point about which combined motion of rotation and translation of a rigid body takes place, is known as Virtual centre Instantaneous centre Instantaneous axis Point of rotation Virtual centre Instantaneous centre Instantaneous axis Point of rotation ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The reaction between the sphere and the wall of the arrangement made is 110 kg 108.5 kg 105.5 kg 102.5 kg 110 kg 108.5 kg 105.5 kg 102.5 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec ANSWER DOWNLOAD EXAMIANS APP
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