Applied Mechanics and Graphic Statics The centre of gravity of a quadrant of a circle lies along its central radius at a distance of 0.6 R 0.3 R 0.4 R 0.2 R 0.6 R 0.3 R 0.4 R 0.2 R ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is y = ω √(y - r) v = ω √(r² - y²) v = ω √(r² + y²) v = ω √(y² - r²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(r² + y²) v = ω √(y² - r²) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The gravitational force makes a satellite go round the earth in a circular orbit, if it is projected with an initial velocity of 11.26 km/sec, the satellite escapes the pull of the earth All listed here 11.11 km/sec at a height of 37,400 km 8.04 km/sec at a height of 285 km 11.26 km/sec, the satellite escapes the pull of the earth All listed here 11.11 km/sec at a height of 37,400 km 8.04 km/sec at a height of 285 km ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rod AB carries three loads of 30 N, 70 N and 100 N at distances of 20 mm, 90 mm and 150 mm respectively from A. Neglecting the weight of the rod, the point at which the rod will balance is 119.5 mm from A 109.5 mm from A 125.5 mm from A 132.5 mm from A 119.5 mm from A 109.5 mm from A 125.5 mm from A 132.5 mm from A ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A simple pendulum of length / has an energy E, when its amplitude is A. If the length of pendulum is doubled, the energy will be E 2E 4E E/2 E 2E 4E E/2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals Q sin θ/P + Q sin θ P sin θ/P - Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ Q sin θ/P + Q sin θ P sin θ/P - Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ ANSWER DOWNLOAD EXAMIANS APP
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