Applied Mechanics and Graphic Statics A bullet weighing 10 gm moves with a velocity of l km/sec. Its kinetic energy is (i) 5000 Nm (ii) 5000 kg.m (iii) 5000 J Both (i) and (iii) Only (ii) All (i), (ii) and (iii) Both (ii) and (iii) Both (i) and (iii) Only (ii) All (i), (ii) and (iii) Both (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The Centre of gravity of a 10 × 15 × 5 cm T section from its bottom, is 8.75 cm 7.5 cm 7.85 cm 5.0 cm 8.75 cm 7.5 cm 7.85 cm 5.0 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The acceleration of a train starting from rest at any instant is 1/6(V + 1) m/sec² where ‘V’ is the velocity of the train in m/sec. The train will attain a velocity of 36 km/hour after travelling a distance of 2000 m 2300 m 2100 m 2200 m 2000 m 2300 m 2100 m 2200 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A bullet weighing 200 g is fired horizontally with a velocity of 25 m/sec from a gun carried on a carriage which together with the gun weighs 100 kg. The velocity of recoil of the gun, will be 1.00 m/sec 0.01 m/sec 0.05 m/sec 1.5 m/see 1.00 m/sec 0.01 m/sec 0.05 m/sec 1.5 m/see ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Parallelogram Law of Forces states, "if two forces acting simultaneously on a particle be represented in magnitude and direction by two adjacent sides of a parallelogram, their resultant may be represented in magnitude and direction by Its shorter side Its longer side The diagonal of the parallelogram which does not pass through the point of intersection of the forces The diagonal of the parallelogram which passes through the point of intersection of the forces Its shorter side Its longer side The diagonal of the parallelogram which does not pass through the point of intersection of the forces The diagonal of the parallelogram which passes through the point of intersection of the forces ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) ANSWER DOWNLOAD EXAMIANS APP
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