Applied Mechanics and Graphic Statics The dimensions of power are. M’L2T2 M’L-‘T* M’L’T3 M’L’r2 M’L2T2 M’L-‘T* M’L’T3 M’L’r2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of an elastic string of natural length ‘l’ and modulus ‘X’ is kept fixed while to the other end is attached a particle of mass m which is hanging freely under gravity. The particle is pulled down vertically through a distance ‘x’, held at rest and then released.The motion is A damped oscillatory motion None of these A rectilinear motion with constant speed A simple harmonic motion A damped oscillatory motion None of these A rectilinear motion with constant speed A simple harmonic motion ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball which is thrown upwards, returns to the ground describing a parabolic path during its flight Vertical component of velocity remains constant Kinetic energy of the ball remains constant Speed of the ball remains constant Horizontal component of velocity remains constant Vertical component of velocity remains constant Kinetic energy of the ball remains constant Speed of the ball remains constant Horizontal component of velocity remains constant ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A marble ball is rolled on a smooth floor of a room to hit a wall. If the time taken by the ball in returning to the point of projection is twice the time taken in reaching the wall, the coefficient of restitution between the ball and the wall, is 0.75 1.0 0.25 0.50 0.75 1.0 0.25 0.50 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The motion of a particle moving with S.H.M. from an extremity to the other, constitutes None of these Two oscillations One full oscillation Half an oscillation None of these Two oscillations One full oscillation Half an oscillation ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M2 - M1)/(M1 + M2) ANSWER DOWNLOAD EXAMIANS APP
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