Applied Mechanics and Graphic Statics The time period of a simple pendulum depends on (i) Mass of suspended particle (ii) Length of the pendulum (iii) Acceleration due to gravity All are correct Both (i) and (iii) Only (i) Both (ii) and (iii) All are correct Both (i) and (iii) Only (i) Both (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics At a given instant ship ‘A’ is travelling at 6 km/h due east and ship ‘B’ is travelling at 8 km/h due north. The velocity of ‘B’ relative to ‘A’ is 2 km/hrs 1 km/hrs 10 km/hrs 7 km/hrs 2 km/hrs 1 km/hrs 10 km/hrs 7 km/hrs ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A shell travelling with a horizontal velocity of 100 m/sec explodes and splits into two parts, one of mass 10 kg and the other of 15 kg. The 15 kg mass drops vertically downward with initial velocity of 100 m/sec and the 10 kg mass begins to travel at an angle to the horizontal of tan”1 x, where x is 3/4 4/5 3/5 5/3 3/4 4/5 3/5 5/3 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The masses of two balls are in the ratio of 2 : 1 and their respective velocities are in the ratio of 1 : 2 but in opposite direction before impact. If the coefficient of restitution is ½, the velocities of separation of the balls will be equal to Original velocity in the same direction Half the original velocity in the same direction Half the original velocity in the opposite direction Original velocity in the opposite direction Original velocity in the same direction Half the original velocity in the same direction Half the original velocity in the opposite direction Original velocity in the opposite direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is, 5 N 10 N 15 N 25 N 5 N 10 N 15 N 25 N ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The intrinsic equation of catenary is y = c cosh ψ S = c tan ψ y = c cosh x/c y = c sinh ψ y = c cosh ψ S = c tan ψ y = c cosh x/c y = c sinh ψ ANSWER DOWNLOAD EXAMIANS APP
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