Applied Mechanics and Graphic Statics The ratio of the ranges on the inclined plane with motion upward and with motion downward for a given velocity, angle of projection will be cos (α - β)/cos (α + β) sin (α + β)/sin (α - β) sin (α - β)/sin (α + β) tan (α - β)/tan (α + β) cos (α - β)/cos (α + β) sin (α + β)/sin (α - β) sin (α - β)/sin (α + β) tan (α - β)/tan (α + β) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body A of mass 6.6 kg which is lying on a horizontal platform 4.5 m from its edge is connected to the end of a light string whose other end is supporting a body of mass 3.2 kg as shown in below figure. If the friction between the platform and the body A is 1/3, the acceleration is 0.5 m/sec² 1.00 m/sec² 1.25 m/sec² 0.75 m/sec² 0.5 m/sec² 1.00 m/sec² 1.25 m/sec² 0.75 m/sec² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The total time of collision and restitution of two bodies, is called Time of collision All listed here Period of impact Period of collision Time of collision All listed here Period of impact Period of collision ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Power developed by a torque, is 2πNT /60 watts 2πNT kg m/min All listed here 2πNT/4500 h.p 2πNT /60 watts 2πNT kg m/min All listed here 2πNT/4500 h.p ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(y² - r²) v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(y² - r²) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angle of projection for a range is equal to the distance through which the particle would have fallen in order to acquire a velocity equal to the velocity of projection, will be 60° 75° 45° 30° 60° 75° 45° 30° ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS