Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals P sin θ/P + Q tan θ Q sin θ/P + Q cos θ Q sin θ/P + Q sin θ P sin θ/P - Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ Q sin θ/P + Q sin θ P sin θ/P - Q cos θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is 10 kg 40 kg 100 kg 60 kg 10 kg 40 kg 100 kg 60 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity ratio of the differential wheel and axle is 2R/r1 + r2 R/r1 - r2 3R/r1 - r2 2R/r1 2R/r1 + r2 R/r1 - r2 3R/r1 - r2 2R/r1 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A retarding force on a body does not Change the motion of the body None of these Retard the motion of the body Introduce the motion of the body Change the motion of the body None of these Retard the motion of the body Introduce the motion of the body ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics M.I. of a thin ring (external diameter D, internal diameter d) about an axis perpendicular to the plane of the ring, is π/32 (D⁴ × d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ + d⁴) π/32 (D⁴ - d⁴) π/32 (D⁴ × d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ + d⁴) π/32 (D⁴ - d⁴) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.5)]/(π + 0.25) [r (π - 0.25)]/(π - 0.5) [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.5)]/(π + 0.25) [r (π - 0.25)]/(π - 0.5) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS