Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals Q sin θ/P + Q cos θ Q sin θ/P + Q sin θ P sin θ/P - Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ Q sin θ/P + Q sin θ P sin θ/P - Q cos θ P sin θ/P + Q tan θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The member which does not carry zero force in the structure shown in below figure, is ED DC BC BD ED DC BC BD ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the linear velocity of a point on the rim of a wheel of 10 m diameter, is 50 m/sec, its angular velocity will be 10 rad/sec 20 rad/sec 5 rad/sec 20 rad/sec 10 rad/sec 20 rad/sec 5 rad/sec 20 rad/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle of mass 2 kg executes simple harmonic motion of frequency 6/71 Hz and amplitude 0.25 m. Its maximum kinetic energy is 12.0 J 4.5 J 9.0 J 18.0 J 12.0 J 4.5 J 9.0 J 18.0 J ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A car goes round a curve of radius 100 m at 25 m/sec. The angle to the horizontal at which the road must be banked to prevent sideways friction on the car wheels is tan"1 x, where x is (Assume g = 10 m/sec²) 43898 43832 44079 43959 43898 43832 44079 43959 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics For a non-concurrent force system to be in equilibrium Both force polygon and funicular polygon must close None of these Only the closure of force polygon is sufficient Only the closure of funicular polygon is sufficient Both force polygon and funicular polygon must close None of these Only the closure of force polygon is sufficient Only the closure of funicular polygon is sufficient ANSWER DOWNLOAD EXAMIANS APP
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