Applied Mechanics and Graphic Statics A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The mechanical advantage of the lifting machine is 15 20 26 18 15 20 26 18 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A circular disc rotates at n rpm. The angular velocity of a circular ring of same mass and radius as the disc and to have the same angular momentum is 2n rpm n/2 rpm n rpm n/4 rpm 2n rpm n/2 rpm n rpm n/4 rpm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The following factor affects the orbit of a satellite up to an altitude of 720 km from the earth's surface None of these Gravity of the sun and the moon Aerodynamic forces Uneven distribution of the gravitational field None of these Gravity of the sun and the moon Aerodynamic forces Uneven distribution of the gravitational field ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A flywheel of moment of inertia 20 kg.m is acted upon by a tangential force of 5 N at 2 m from its axis, for 3 seconds. The increase in angular velocity in radian per second is 3 43892 43832 2 3 43892 43832 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The gravitational force makes a satellite go round the earth in a circular orbit, if it is projected with an initial velocity of 8.04 km/sec at a height of 285 km 11.11 km/sec at a height of 37,400 km All listed here 11.26 km/sec, the satellite escapes the pull of the earth 8.04 km/sec at a height of 285 km 11.11 km/sec at a height of 37,400 km All listed here 11.26 km/sec, the satellite escapes the pull of the earth ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ P² + Q² + 2PQ tan θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ P² + Q² + 2PQ tan θ ANSWER DOWNLOAD EXAMIANS APP
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