Applied Mechanics and Graphic Statics A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The mechanical advantage of the lifting machine is 20 18 26 15 20 18 26 15 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the velocity of projection is 4 m/sec and the angle of projection is α°, the maximum height of the projectile from a horizontal plane, is u² sin² α/2g u² sin 2α/2g u² cos² α/2g u² tan² α/2g u² sin² α/2g u² sin 2α/2g u² cos² α/2g u² tan² α/2g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is, 25 N 10 N 5 N 15 N 25 N 10 N 5 N 15 N ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Newton’s Law of Motion is: To every action, there is always an equal and opposite reaction All listed here The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction, in which the force acts Everybody continues in its state of rest or of uniform motion in a straight line, unless it is acted upon by some external force To every action, there is always an equal and opposite reaction All listed here The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction, in which the force acts Everybody continues in its state of rest or of uniform motion in a straight line, unless it is acted upon by some external force ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two balls of masses 3 kg and 6 kg are moving with velocities of 4 m/sec and 1 m/sec respectively, towards each other along the line of their centers. After impact the 3 kg ball comes to rest. This can happen only if the coefficient of restitution between the balls is 1/5 1/3 3/5 2/3 1/5 1/3 3/5 2/3 ANSWER DOWNLOAD EXAMIANS APP
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