Applied Mechanics and Graphic Statics If two forces each equal to ‘T’ in magnitude act at right angles, their effect may be neutralized by a third force acting along their bisector in opposite direction whose magnitude will be 1/2 T √2 T 3 T 2 T 1/2 T √2 T 3 T 2 T ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The member which does not carry zero force in the structure shown in below figure, is Applied Mechanics and Graphic Statics mcq question image BD BC DC ED BD BC DC ED ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(y² - r²) v = ω √(r² - y²) v = ω √(r² + y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² - y²) v = ω √(r² + y²) y = ω √(y - r) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Varingon’s theorem of moment’s states Arithmetical sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Algebraic sum of the moments of two forces about any point, is equal to the moment of their resultant about that point Algebraic sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Arithmetical sum of the moments of two forces about any point, is equal to the moments of their resultant about that point Arithmetical sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Algebraic sum of the moments of two forces about any point, is equal to the moment of their resultant about that point Algebraic sum of the moments of the forces about any point in their plane, is equal to the moment of their resultant about that point Arithmetical sum of the moments of two forces about any point, is equal to the moments of their resultant about that point ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A string of length 90 cm is fastened to two points ‘A’ and ‘B’ at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force ‘P’ is applied to the ring such that it is in equilibrium vertically below ‘B’. The value of ‘P’ is: 60 g 80 g 100 g 40 g 60 g 80 g 100 g 40 g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of Applied Mechanics and Graphic Statics mcq question image (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
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