Applied Mechanics and Graphic Statics The equation of motion of a particle starting from rest along a straight line is x = t³ - 3t²+ 5. The ratio of the accelerations after 5 sec and 3 sec will be 4 3 5 2 4 3 5 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Impulse can be obtained from a Force-displacement diagram Velocity-displacement diagram Force-time diagram Velocity-time diagram Force-displacement diagram Velocity-displacement diagram Force-time diagram Velocity-time diagram ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If A is the amplitude of particle executing simple harmonic motion, then the total energy E of the particle is Proportional to A Proportional to 1/A² Independent of A Proportional to A² Proportional to A Proportional to 1/A² Independent of A Proportional to A² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of a plane lamina will not be at its geometrical centre if it is a Rectangle Right angled triangle Equilateral triangle Circle Rectangle Right angled triangle Equilateral triangle Circle ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2PQ cos θ P² + Q² + 2PQ tan θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2P sin θ P² + Q² + 2PQ cos θ P² + Q² + 2PQ tan θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2P sin θ ANSWER DOWNLOAD EXAMIANS APP