Applied Mechanics and Graphic Statics In case of S.H.M. the period of oscillation (T), is given by T = 2/ω T = π/2ω T = 2ω/π² T = 2π/ω T = 2/ω T = π/2ω T = 2ω/π² T = 2π/ω ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² v = 1/√(2gh) v = 2gh v = √(2gh) v = 2gh² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Newton is equivalent to 1 kg. wt 1/9.81 kg. wt 981 dyne 9.81 kg. wt 1 kg. wt 1/9.81 kg. wt 981 dyne 9.81 kg. wt ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a body is lying on a plane whose inclination with the horizontal is less than the angle of friction, then i. a force is required to move the body upwards ii. a force is required to move the body downward iii. the body will not be in equilibrium The correct answer is both (i) and (ii) both (i) and (iii) only (i) only (ii) both (i) and (ii) both (i) and (iii) only (i) only (ii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The moment of inertia of a triangular section (base b, height h) about centroidal axis parallel to the base, is bh³/3 bh³/36 bh³/2 b³h/12 bh³/3 bh³/36 bh³/2 b³h/12 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A Second's pendulum gains 2 minutes a day. To make it to keep correct time its length Must be increased Is not changed but weight of the bob is decreased Is not changed but weight of the bob is increased Must be decreased Must be increased Is not changed but weight of the bob is decreased Is not changed but weight of the bob is increased Must be decreased ANSWER DOWNLOAD EXAMIANS APP
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