Applied Mechanics and Graphic Statics In case of S.H.M. the period of oscillation (T), is given by T = π/2ω T = 2ω/π² T = 2/ω T = 2π/ω T = π/2ω T = 2ω/π² T = 2/ω T = 2π/ω ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two forces P and Q (P > Q) act on the same straight line but in opposite direction, their resultant, is P/Q Q/P P - Q P + Q P/Q Q/P P - Q P + Q ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The torque produced by a force depends oni. the magnitude of the forceii. the direction of the forceiii. the point of application of the force relative to originThe correct answer is both (i) and (ii) only (i) all (i), (ii) and (iii) both (i) and (iii) both (i) and (ii) only (i) all (i), (ii) and (iii) both (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a body is lying on a plane whose inclination with the horizontal is less than the angle of friction, then i. a force is required to move the body upwards ii. a force is required to move the body downward iii. the body will not be in equilibrium The correct answer is both (i) and (ii) only (i) only (ii) both (i) and (iii) both (i) and (ii) only (i) only (ii) both (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The masses of two balls are in the ratio of 2 : 1 and their respective velocities are in the ratio of 1 : 2 but in opposite direction before impact. If the coefficient of restitution is ½, the velocities of separation of the balls will be equal to Half the original velocity in the opposite direction Original velocity in the same direction Half the original velocity in the same direction Original velocity in the opposite direction Half the original velocity in the opposite direction Original velocity in the same direction Half the original velocity in the same direction Original velocity in the opposite direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/2) × [(2b + a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
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