Applied Mechanics and Graphic Statics If two forces are in equilibrium, then the forces must(i) Be equal in magnitude(ii) Be opposite in sense(iii) Act along the same line (i) and (ii) All (i), (ii) and (iii) (i) and (iii) Only (i) (i) and (ii) All (i), (ii) and (iii) (i) and (iii) Only (i) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics From a solid cylinder of height 8 cm and radius 4 cm, a right circular cone is scooped out on the same base and having the same height as that of the cylinder. The C.G. of the remainder is at a height of 5.0 cm 4.5 cm 5.5 cm 5.25 cm 5.0 cm 4.5 cm 5.5 cm 5.25 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A solid sphere of mass M and radius R rolls down a plane inclined at 0 with the horizontal. The acceleration of sphere is (where g is acceleration due to gravity) (3/7) g sin 0 (1/3) g sin0 (5/7) g sin0 (2/5) g sin 0 (3/7) g sin 0 (1/3) g sin0 (5/7) g sin0 (2/5) g sin 0 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of a trapezoidal dam section whose top width is a, bottom width is band the vertical side is a, from its vertical face is (a² + ab + b²)/3 (a + b) (a² + ab + c²)/3 (a + c) None of these (b² + bc + c²)/3 (b + c) (a² + ab + b²)/3 (a + b) (a² + ab + c²)/3 (a + c) None of these (b² + bc + c²)/3 (b + c) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then, P = Q None of these P = R Q = R P = Q None of these P = R Q = R ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) ANSWER DOWNLOAD EXAMIANS APP
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