Applied Mechanics and Graphic Statics The total kinetic energy of a hoop of mass 2 kg and radius 4 m sliding with linear velocity 8 m/sec and angular velocity 5 radian/sec is 400 J 464 J 89 J 64 J 400 J 464 J 89 J 64 J ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Minimum pull in a suspended cable with supports at two ends is equal to Support reactions Resultant of horizontal thrust and support reaction Horizontal thrust Half the weight of the cable Support reactions Resultant of horizontal thrust and support reaction Horizontal thrust Half the weight of the cable ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two circular discs of same weight and thickness are made from metals having different densities. Which disc will have the larger rotational inertia about its central axis? Disc with larger density None of these Disc with smaller density Both discs will have same rotational inertia Disc with larger density None of these Disc with smaller density Both discs will have same rotational inertia ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of an elastic string of natural length / and modulus X is kept fixed while to the other end is attached a particle of mass m which is hanging freely under gravity. The particle is pulled down vertically through a distance x, held at rest and then released. The motion is a simple harmonic motion None of these a damped oscillatory motion a rectilinear motion with constant speed a simple harmonic motion None of these a damped oscillatory motion a rectilinear motion with constant speed ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The angle which an inclined surface makes with the horizontal when a body placed on it is on the point of moving down, is called None of these Angle of repose Angle of inclination Angle of friction None of these Angle of repose Angle of inclination Angle of friction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 - M1)/(M1 + M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 - M2)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 + M2)/(M1 × M2) ANSWER DOWNLOAD EXAMIANS APP
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