Applied Mechanics and Graphic Statics Free body diagram is an None of these Isolated joint with internal forces acting on it Isolated joint with only body forces acting on it Isolated joint with all the forces, internal as well as external, acting on it None of these Isolated joint with internal forces acting on it Isolated joint with only body forces acting on it Isolated joint with all the forces, internal as well as external, acting on it ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A bullet weighing 10 gm moves with a velocity of l km/sec. Its kinetic energy is (i) 5000 Nm (ii) 5000 kg.m (iii) 5000 J Both (i) and (iii) Both (ii) and (iii) All (i), (ii) and (iii) Only (ii) Both (i) and (iii) Both (ii) and (iii) All (i), (ii) and (iii) Only (ii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball moving on a smooth horizontal table hits a rough vertical wall, the coefficient of restitution between ball and wall being 1/3. The ball rebounds at the same angle. The fraction of its kinetic energy lost is 43864 43839 43833 44052 43864 43839 43833 44052 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The ratio of the ranges on the inclined plane with motion upward and with motion downward for a given velocity, angle of projection will be sin (α - β)/sin (α + β) sin (α + β)/sin (α - β) cos (α - β)/cos (α + β) tan (α - β)/tan (α + β) sin (α - β)/sin (α + β) sin (α + β)/sin (α - β) cos (α - β)/cos (α + β) tan (α - β)/tan (α + β) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a body is lying on a plane whose inclination with the horizontal is less than the angle of friction, then i. a force is required to move the body upwards ii. a force is required to move the body downward iii. the body will not be in equilibrium The correct answer is only (ii) both (i) and (iii) only (i) both (i) and (ii) only (ii) both (i) and (iii) only (i) both (i) and (ii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The intrinsic equation of catenary is y = c sinh ψ S = c tan ψ y = c cosh x/c y = c cosh ψ y = c sinh ψ S = c tan ψ y = c cosh x/c y = c cosh ψ ANSWER DOWNLOAD EXAMIANS APP
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