Applied Mechanics and Graphic Statics If g1 and g2 are the gravitational accelerations on two mountains A and B respectively, the weight of a body when transported from A to B will be multiplied by g2/g1 g1 g2 g1/g2 g2/g1 g1 g2 g1/g2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics M.I. of a thin ring (external diameter D, internal diameter d) about an axis perpendicular to the plane of the ring, is π/32 (D⁴ - d⁴) π/32 (D⁴ × d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ + d⁴) π/32 (D⁴ - d⁴) π/32 (D⁴ × d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ + d⁴) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resolved part of the resultant of two forces inclined at an angle θ in a given direction is Arithmetical sum of the resolved parts of the forces in the direction Algebraic sum of the resolved parts of the forces in the direction Difference of the forces multiplied by cosine θ° Sum of the forces multiplied by the tangent θ° Arithmetical sum of the resolved parts of the forces in the direction Algebraic sum of the resolved parts of the forces in the direction Difference of the forces multiplied by cosine θ° Sum of the forces multiplied by the tangent θ° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a body is lying on a plane whose inclination with the horizontal is less than the angle of friction, theni. a force is required to move the body upwardsii. a force is required to move the body downwardiii. the body will not be in equilibriumThe correct answer is only (i) both (i) and (ii) both (i) and (iii) only (ii) only (i) both (i) and (ii) both (i) and (iii) only (ii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The time period of a simple pendulum depends on(i) Mass of suspended particle(ii) Length of the pendulum(iii) Acceleration due to gravity Only (i) Both (ii) and (iii) All are correct Both (i) and (iii) Only (i) Both (ii) and (iii) All are correct Both (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A uniform rod 9 m long weighing 40 kg is pivoted at a point 2 m from one end where a weight of 120 kg is suspended. The required force acting at the end in a direction perpendicular to rod to keep it equilibrium, at an inclination 60° with horizontal, is 40 kg 10 kg 60 kg 100 kg 40 kg 10 kg 60 kg 100 kg ANSWER DOWNLOAD EXAMIANS APP
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