Applied Mechanics and Graphic Statics If g1 and g2 are the gravitational accelerations on two mountains A and B respectively, the weight of a body when transported from A to B will be multiplied by g2/g1 g1 g1/g2 g2 g2/g1 g1 g1/g2 g2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The maximum displacement of a particle executing S.H.M. corresponds to Zero kinetic energy and maximum potential energy Minimum kinetic energy and minimum potential energy Maximum kinetic energy and maximum potential energy Zero potential energy and maximum kinetic energy Zero kinetic energy and maximum potential energy Minimum kinetic energy and minimum potential energy Maximum kinetic energy and maximum potential energy Zero potential energy and maximum kinetic energy ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The maximum velocity of a body vibrating with a simple harmonic motion of amplitude 150 mm and frequency 2 vibrations/sec, is 18.85 m/sec 1.885 m/sec 0.18845 m/sec 188.5 m/sec 18.85 m/sec 1.885 m/sec 0.18845 m/sec 188.5 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of the forces acting on a body will be zero if the body Moves with variable velocity in a straight line Rotates Moves along a curved path Does not move at all Moves with variable velocity in a straight line Rotates Moves along a curved path Does not move at all ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The phenomenon of collision of two elastic bodies takes place because bodies Tend to compress each other till they are compressed maximum possible All listed here Immediately after collision come momentarily to rest Attempt to regain its original shape due to their elasticities Tend to compress each other till they are compressed maximum possible All listed here Immediately after collision come momentarily to rest Attempt to regain its original shape due to their elasticities ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The intrinsic equation of catenary is S = c tan ψ y = c sinh ψ y = c cosh x/c y = c cosh ψ S = c tan ψ y = c sinh ψ y = c cosh x/c y = c cosh ψ ANSWER DOWNLOAD EXAMIANS APP
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