Applied Mechanics and Graphic Statics At the instantaneous center, the velocity of the moving lamina at any instant is Zero Minimum Varying Maximum Zero Minimum Varying Maximum ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A funicular polygon cannot be made to pass through More than three specified points One specified point Two specified points Three specified points More than three specified points One specified point Two specified points Three specified points ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Two forces act an angle of 120°. If the greater force is 50 kg and their resultant is perpendicular to the smaller force, the smaller force is 50 kg 25 kg 40 kg 30 kg 50 kg 25 kg 40 kg 30 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals Q sin θ/P + Q sin θ Q sin θ/P + Q cos θ P sin θ/P + Q tan θ P sin θ/P - Q cos θ Q sin θ/P + Q sin θ Q sin θ/P + Q cos θ P sin θ/P + Q tan θ P sin θ/P - Q cos θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The moment of inertia of a circular lamina of diameter ‘d’, about an axis perpendicular to the plane of the lamina and passing through its centre, is πd⁴/24 π/64 (D⁴ + d⁴) πd⁴/16 πd⁴/32 πd⁴/24 π/64 (D⁴ + d⁴) πd⁴/16 πd⁴/32 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
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