Applied Mechanics and Graphic Statics A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is, 10 N 5 N 15 N 25 N 10 N 5 N 15 N 25 N ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resolved part of the resultant of two forces inclined at an angle θ in a given direction is Algebraic sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Difference of the forces multiplied by cosine θ° Arithmetical sum of the resolved parts of the forces in the direction Algebraic sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Difference of the forces multiplied by cosine θ° Arithmetical sum of the resolved parts of the forces in the direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Minimum pull in a suspended cable with supports at two ends is equal to Half the weight of the cable Resultant of horizontal thrust and support reaction Support reactions Horizontal thrust Half the weight of the cable Resultant of horizontal thrust and support reaction Support reactions Horizontal thrust ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body is said to move with Simple Harmonic Motion if its acceleration, is Proportional to the square of the distance from the point of reference Always directed away from the centre, the point of reference Inversely proportion to the distance from the point of reference Proportional to the distance from the point of reference and directed towards it Proportional to the square of the distance from the point of reference Always directed away from the centre, the point of reference Inversely proportion to the distance from the point of reference Proportional to the distance from the point of reference and directed towards it ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The intrinsic equation of catenary is S = c tan ψ y = c cosh x/c y = c sinh ψ y = c cosh ψ S = c tan ψ y = c cosh x/c y = c sinh ψ y = c cosh ψ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Time period and length of a second’s pendulum respectively are 2 sec and 92.7 cm 2 sec and 99.4 cm 1 sec and 99.4 cm 1 sec and 92.7 cm 2 sec and 92.7 cm 2 sec and 99.4 cm 1 sec and 99.4 cm 1 sec and 92.7 cm ANSWER DOWNLOAD EXAMIANS APP
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