Applied Mechanics and Graphic Statics A stone of mass 1 kg is tied to a string of length 1 m and whirled in a horizontal circle at a constant angular speed 5 rad/sec. The tension in the string is, 5 N 25 N 10 N 15 N 5 N 25 N 10 N 15 N ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A 2 m long ladder rests against a wall and makes an angle of 30° with the horizontal floor. Where will be the instantaneous center of rotation when the ladder starts slipping ? i. 1.0 in from the wall ii. 1.732 m from the wall iii. 1.0 m above the floor iv. 1.732 m above the floor The correct answer is (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals P sin θ/P - Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ Q sin θ/P + Q sin θ P sin θ/P - Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ Q sin θ/P + Q sin θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A shell travelling with a horizontal velocity of 100 m/sec explodes and splits into two parts, one of mass 10 kg and the other of 15 kg. The 15 kg mass drops vertically downward with initial velocity of 100 m/sec and the 10 kg mass begins to travel at an angle to the horizontal of tan”1 x, where x is 43895 43894 43954 43926 43895 43894 43954 43926 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves in a straight line and its position is defined by the equation x = 6 t² - t3 where t is expressed in seconds and ‘x’ in meters. The maximum velocity during the motion is 6 m/sec 48 m/sec 24 m/sec 12 m/sec 6 m/sec 48 m/sec 24 m/sec 12 m/sec ANSWER DOWNLOAD EXAMIANS APP
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