Applied Mechanics and Graphic Statics A system of coplanar forces acting on a rigid body can be reduced to None of these One couple only One force and one couple only One force only None of these One couple only One force and one couple only One force only ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball moving with a velocity of 5 m/sec impinges a fixed plane at an angle of 45° and its direction after impact is equally inclined to the line of impact. If the coefficient of restitution is 0.5, the velocity of the ball after impact will be 1.5 m/sec 2.5 m/sec 0.5 m/sec 3.5 m/sec 1.5 m/sec 2.5 m/sec 0.5 m/sec 3.5 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The member forces in a statically in determinate truss Can be obtained by graphic statics by trial and error Can be obtained by graphic statics May be obtained by graphic statics Cannot be obtained by graphic statics Can be obtained by graphic statics by trial and error Can be obtained by graphic statics May be obtained by graphic statics Cannot be obtained by graphic statics ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) [r (π + 0.25)]/(π - 0.5) [r (π + 0.25)]/(π + 0.5) [r (π - 0.25)]/(π - 0.5) [r (π - 0.5)]/(π + 0.25) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2P sin θ P² + Q² + 2PQ tan θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ P² + Q² + 2PQ tan θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals P sin θ/P + Q tan θ P sin θ/P - Q cos θ Q sin θ/P + Q sin θ Q sin θ/P + Q cos θ P sin θ/P + Q tan θ P sin θ/P - Q cos θ Q sin θ/P + Q sin θ Q sin θ/P + Q cos θ ANSWER DOWNLOAD EXAMIANS APP
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