Applied Mechanics and Graphic Statics A ball of mass 1 kg moving with a velocity of 2 m/sec collides a stationary ball of mass 2 kg and comes to rest after impact. The velocity of the second ball after impact will be 1.0 m/sec 0.5 m/sec 2.0 m/sec Zero 1.0 m/sec 0.5 m/sec 2.0 m/sec Zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A point subjected to a number of forces will be in equilibrium, if Algebraic sum of the forces is zero Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the moments of the forces about the point is zero Two resolved parts in any two directions at right angles are equal Algebraic sum of the forces is zero Sum of resolved parts in any two directions at right angles, are both zero Algebraic sum of the moments of the forces about the point is zero Two resolved parts in any two directions at right angles are equal ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A cube on a smooth horizontal surface Cannot be in stable equilibrium Cannot be in unstable equilibrium Can be in any of these states Cannot be in neutral equilibrium Cannot be in stable equilibrium Cannot be in unstable equilibrium Can be in any of these states Cannot be in neutral equilibrium ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the velocity of projection is 4 m/sec and the angle of projection is α°, the maximum height of the projectile from a horizontal plane, is u² tan² α/2g u² sin² α/2g u² cos² α/2g u² sin 2α/2g u² tan² α/2g u² sin² α/2g u² cos² α/2g u² sin 2α/2g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If ‘α’ is the angular acceleration of a compound pendulum whose angular displacement is ‘θ’, the frequency of the motion is (1/2π) √(α/θ) 2π √(α - θ) 2π √(α/θ) 4π √(α/θ) (1/2π) √(α/θ) 2π √(α - θ) 2π √(α/θ) 4π √(α/θ) ANSWER DOWNLOAD EXAMIANS APP
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