Applied Mechanics and Graphic Statics A ball of mass 1 kg moving with a velocity of 2 m/sec collides a stationary ball of mass 2 kg and comes to rest after impact. The velocity of the second ball after impact will be 1.0 m/sec Zero 2.0 m/sec 0.5 m/sec 1.0 m/sec Zero 2.0 m/sec 0.5 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Williot-Mohr diagram is used to determine deflection in Any type of structure Rigid frames only Beam only Trusses only Any type of structure Rigid frames only Beam only Trusses only ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The torque produced by a force depends on i. the magnitude of the force ii. the direction of the force iii. the point of application of the force relative to origin The correct answer is both (i) and (ii) all (i), (ii) and (iii) both (i) and (iii) only (i) both (i) and (ii) all (i), (ii) and (iii) both (i) and (iii) only (i) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body slides down an inclined surface, the acceleration (f) of the body, is given by f = g sin θ f = g cos θ f = g tan θ f = g f = g sin θ f = g cos θ f = g tan θ f = g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is 40 sec 20 sec 15 sec 30 sec 40 sec 20 sec 15 sec 30 sec ANSWER DOWNLOAD EXAMIANS APP
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