Applied Mechanics and Graphic Statics When a body slides down an inclined surface, the acceleration (f) of the body, is given by f = g cos θ f = g f = g sin θ f = g tan θ f = g cos θ f = g f = g sin θ f = g tan θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the kinetic energy and potential energy of a simple harmonic oscillator of amplitude A are both equal to half the total energy, then the displacement is equal to A A/2 A/√2 A√2 A A/2 A/√2 A√2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The graphical method of determining the forces in the members of a truss is based on None of the two methods Either method Method of joint Method of section None of the two methods Either method Method of joint Method of section ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The rate of change of displacement of a body with respect to its surrounding, is known Speed Velocity None of these Acceleration Speed Velocity None of these Acceleration ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rod 5 m in length is moving in a vertical plane. When it is inclined at 60° to horizontal, its lower end is moving horizontally at 3 m/sec and upper end is moving in vertical direction. The velocity of its upper end, is 0.5 m/sec 1.0 m/sec 1.5 m/sec 2.5 m/sec 0.5 m/sec 1.0 m/sec 1.5 m/sec 2.5 m/sec ANSWER DOWNLOAD EXAMIANS APP
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