Applied Mechanics and Graphic Statics When a body slides down an inclined surface, the acceleration (f) of the body, is given by f = g sin θ f = g tan θ f = g cos θ f = g f = g sin θ f = g tan θ f = g cos θ f = g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the angle between the applied force and the direction of motion of a body, is between 90° and 180°, the work done, is called Virtual work Negative work Imaginary work Zero work Virtual work Negative work Imaginary work Zero work ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics From a solid cylinder of height 8 cm and radius 4 cm, a right circular cone is scooped out on the same base and having the same height as that of the cylinder. The C.G. of the remainder is at a height of 4.5 cm 5.5 cm 5.0 cm 5.25 cm 4.5 cm 5.5 cm 5.0 cm 5.25 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A quantity whose dimensions are M2L2T3 could be the product of energy and velocity force and pressure force and velocity mass and power energy and velocity force and pressure force and velocity mass and power ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A string of length 90 cm is fastened to two points ‘A’ and ‘B’ at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force ‘P’ is applied to the ring such that it is in equilibrium vertically below ‘B’. The value of ‘P’ is: 80 g 60 g 40 g 100 g 80 g 60 g 40 g 100 g ANSWER DOWNLOAD EXAMIANS APP
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