Applied Mechanics and Graphic Statics When a body slides down an inclined surface, the acceleration (f) of the body, is given by f = g f = g tan θ f = g sin θ f = g cos θ f = g f = g tan θ f = g sin θ f = g cos θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics M.I. of a thin ring (external diameter D, internal diameter d) about an axis perpendicular to the plane of the ring, is π/32 (D⁴ - d⁴) π/32 (D⁴ + d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ × d⁴) π/32 (D⁴ - d⁴) π/32 (D⁴ + d⁴) π/64 (D⁴ + d⁴) π/32 (D⁴ × d⁴) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A weight of 100 kg is supported by a string whose ends are attached to pegs ‘A’ and ‘B’ at the same level shown in below figure. The tension in the string is 750 kg 50 kg 120 kg 100 kg 750 kg 50 kg 120 kg 100 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In simple harmonic motion, acceleration of a particle is proportional to Direction Velocity Rate of change of velocity Displacement Direction Velocity Rate of change of velocity Displacement ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² + y²) v = ω √(r² - y²) y = ω √(y - r) v = ω √(y² - r²) v = ω √(r² + y²) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the tension in a cable supporting a lift moving upwards is twice the tension when the lift is moving downwards, the acceleration of the lift, is g/4 g/2 g/3 g/5 g/4 g/2 g/3 g/5 ANSWER DOWNLOAD EXAMIANS APP
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