Applied Mechanics and Graphic Statics The member which does not carry zero force in the structure shown in below figure, is DC BD ED BC DC BD ED BC ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2PQ tan θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ P² + Q² + 2PQ tan θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2P sin θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. The angle of friction is 19° 48' 18° 48' 20° 48' 17° 48' 19° 48' 18° 48' 20° 48' 17° 48' ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Joule is equivalent to 1 dyne metre 1 kg wt metre 9.81 Newton metre 1 Newton metre 1 dyne metre 1 kg wt metre 9.81 Newton metre 1 Newton metre ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In case of S.H.M. the period of oscillation (T), is given by T = π/2ω T = 2π/ω T = 2ω/π² T = 2/ω T = π/2ω T = 2π/ω T = 2ω/π² T = 2/ω ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Maximum efficiency of a screw jack for the angle of friction θ, is (1 + sin θ)/(1 - sin θ) (1 - sin θ)/(1 + sin θ) sin θ/(1 + sin θ) (1 - sin θ)/sin θ (1 + sin θ)/(1 - sin θ) (1 - sin θ)/(1 + sin θ) sin θ/(1 + sin θ) (1 - sin θ)/sin θ ANSWER DOWNLOAD EXAMIANS APP
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