Applied Mechanics and Graphic Statics The member which does not carry zero force in the structure shown in below figure, is BD ED BC DC BD ED BC DC ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Cartesian form of the equation of catenary is y = c tan x/c y = c cosh x/c y = c sinh x/c y = c sin x/c y = c tan x/c y = c cosh x/c y = c sinh x/c y = c sin x/c ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The shape of a suspended cable for a uniformly distributed load over it is Parabolic Catenary Cubic parabola Circular Parabolic Catenary Cubic parabola Circular ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The phenomenon of collision of two elastic bodies takes place because bodies Tend to compress each other till they are compressed maximum possible Immediately after collision come momentarily to rest Attempt to regain its original shape due to their elasticities All listed here Tend to compress each other till they are compressed maximum possible Immediately after collision come momentarily to rest Attempt to regain its original shape due to their elasticities All listed here ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2PQ cos θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ P² + Q² + 2PQ cos θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ ANSWER DOWNLOAD EXAMIANS APP
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