Applied Mechanics and Graphic Statics The angles between two forces to make their resultant a minimum and a maximum respectively are 90° and 180° 0° and 90° 180° and 0° 180° and 90° 90° and 180° 0° and 90° 180° and 0° 180° and 90° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A string of length 90 cm is fastened to two points ‘A’ and ‘B’ at the same level 60 cm apart. A ring weighing 120 g is slided on the string. A horizontal force ‘P’ is applied to the ring such that it is in equilibrium vertically below ‘B’. The value of ‘P’ is: 40 g 60 g 100 g 80 g 40 g 60 g 100 g 80 g ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The beam shown in below figure is supported by a hinge at ‘A’ and a roller at ‘B’. The reaction RA of the hinged support ‘A’ of the beam, is 10.2 t 10.4 t 10.6 t 10.8 t 10.2 t 10.4 t 10.6 t 10.8 t ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In simple harmonic motion, acceleration of a particle is proportional to Direction Displacement Rate of change of velocity Velocity Direction Displacement Rate of change of velocity Velocity ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The displacement of a particle which moves along a straight line is given by S = 4t³ + 3t²- 10 where ‘S’ is in meters and t is in seconds. The time taken by the particle to acquire a velocity of 18 m/sec from rest, is 1.5 sec 1.2 sec 1 sec ½ sec 1.5 sec 1.2 sec 1 sec ½ sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M2 - M1)/(M1 + M2) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) T = g(M2 - M1)/(M1 + M2) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) ANSWER DOWNLOAD EXAMIANS APP
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