RCC Structures Design The stresses developed in concrete and steel in reinforced concrete beam 25 cm width and 70 cm effective depth, are 62.5 kg/cm² and 250 kg/cm² respectively. If m = 15, the depth of its neutral axis is 30 cm 35 cm 20 cm 25 cm 30 cm 35 cm 20 cm 25 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design After pre-stressing process is completed, a loss of stress is due to Creep of concrete Shrinkage of concrete All of the listed here Elastic shortening of concrete Creep of concrete Shrinkage of concrete All of the listed here Elastic shortening of concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘W’ is weight of a retaining wall and ‘P’ is the horizontal earth pressure, the factor of safety against sliding, is 1.5 2.0 3.0 1.0 1.5 2.0 3.0 1.0 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As the percentage of steel increases Lever arm increases Lever arm decreases Depth of neutral axis decreases Depth of neutral axis increases Lever arm increases Lever arm decreases Depth of neutral axis decreases Depth of neutral axis increases ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/4a²bq D = W (a² - b²)/8a²bq D = W (a - b)/4a²bq D = W (a² - b²)/4abq D = W (a² - b²)/4a²bq D = W (a² - b²)/8a²bq D = W (a - b)/4a²bq D = W (a² - b²)/4abq ANSWER DOWNLOAD EXAMIANS APP
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