RCC Structures Design If P kg/m² is the upward pressure on the slab of a plain concrete footing whose projection on either side of the wall is a cm, the depth of foundation D is given by D = 0.775 Pa D = 0.00775 aP D = 0.0775 aP D = 0.07775 aP D = 0.775 Pa D = 0.00775 aP D = 0.0775 aP D = 0.07775 aP ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to I.S. : 456 specifications, the safe diagonal tensile stress for M 150 grade concrete, is 10 kg/cm² 5 kg/cm² 15 kg/cm² 20 kg/cm² 10 kg/cm² 5 kg/cm² 15 kg/cm² 20 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The thickness of the topping of a ribbed slab, varies between 5 cm to 8 cm 12 cm to 15 cm 8 cm to 10 cm 3 cm to 5 cm 5 cm to 8 cm 12 cm to 15 cm 8 cm to 10 cm 3 cm to 5 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm², the share stirrups are provided for a distance ‘x’ from either end where, ‘x’ is 150 cm 50 cm 200 cm 100 cm 150 cm 50 cm 200 cm 100 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design After pre-stressing process is completed, a loss of stress is due to All of the listed here Creep of concrete Shrinkage of concrete Elastic shortening of concrete All of the listed here Creep of concrete Shrinkage of concrete Elastic shortening of concrete ANSWER DOWNLOAD EXAMIANS APP
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