RCC Structures Design A pile of length ‘L’ carrying a uniformly distributed load ‘W’ per metre length is suspended at the centre and from other two points 0.15 L from either end ; the maximum hogging moment will be WL²/15 WL²/30 WL²/90 WL²/60 WL²/15 WL²/30 WL²/90 WL²/60 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p₁ and p₂ are mutually perpendicular principal stresses acting on a soil mass, the normal stress on any plane inclined at angle θ° to the principal plane carrying the principal stress p₁, is: [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] cos 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] cos 2θ [(p₁ - p₂)/2] + [(p₁ + p₂)/2] sin 2θ [(p₁ + p₂)/2] + [(p₁ - p₂)/2] sin 2θ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-cast pile generally used, is Circular Square Octagonal Square with corners chamfered Circular Square Octagonal Square with corners chamfered ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The section of a reinforced beam where most distant concrete fibre in compression and tension in steel attains permissible stresses simultaneously, is called Critical section Balanced section All listed here Economic section Critical section Balanced section All listed here Economic section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Leaver arm/(Bending moment × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS