RCC Structures Design In a singly reinforced beam Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Plane sections transverse to the centre line of the beam before bending remain plane after bending Compression is borne entirely by concrete Steel possesses initial stresses when embedded in concrete Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Plane sections transverse to the centre line of the beam before bending remain plane after bending Compression is borne entirely by concrete Steel possesses initial stresses when embedded in concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Bottom bars under the columns are extended into the interior of the footing slab to a distance greater than 24 diameters from the centre of the column 42 diameters from the inner edge of the column 42 diameters from the outer edge of the column 42 diameters from the centre of the column 24 diameters from the centre of the column 42 diameters from the inner edge of the column 42 diameters from the outer edge of the column 42 diameters from the centre of the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A very comfortable type of stairs is Dog legged Straight Open newel Geometrical Dog legged Straight Open newel Geometrical ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Minimum spacing between horizontal parallel reinforcement of different sizes, should not be less than One diameter of thinner bar Twice the diameter of thinner bar One diameter of thicker bar None of these One diameter of thinner bar Twice the diameter of thinner bar One diameter of thicker bar None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The diameter of main bars in R.C.C. columns, shall not be less than 12 mm 11 mm 15 mm 10 mm 12 mm 11 mm 15 mm 10 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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