RCC Structures Design The maximum ratio of span to depth of a cantilever slab, is 10 8 12 16 10 8 12 16 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of an intermediate span of a continuous slab is 5 m, the length of the end span is kept 4.0 m 4.5 m 4.1 m 4.7 m 4.0 m 4.5 m 4.1 m 4.7 m ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Based on punching shear consideration, the overall depth of a combined footing under a column A, is (Area of the column A × Safe punching stress)/Load on column A (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) None of these (Area of the column A × Safe punching stress)/Load on column A (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The length of lap in tension reinforcement should not be less than the bar diameter × (actual tension / four times the permissible average bond stress) if it is more than 18 bar diameters 36 bar diameters 24 bar diameters 30 bar diameters 18 bar diameters 36 bar diameters 24 bar diameters 30 bar diameters ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Long and short spans of a two way slab are ly and lx and load on the slab acting on strips parallel to lx and ly be wx and wy respectively. According to Rankine Grashoff theory (wx/wy) = (ly/lx)⁴ None of these (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)² (wx/wy) = (ly/lx)⁴ None of these (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)² ANSWER DOWNLOAD EXAMIANS APP
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