RCC Structures Design The maximum ratio of span to depth of a cantilever slab, is 16 8 10 12 16 8 10 12 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to I.S. : 456, slabs which span in two directions with corners held down, are assumed to be divided in each direction into middle strips and edge strips such that the width of the middle strip, is Three-fourth of the width of the slab Two-third of the width of the slab Four-fifth of the width of the slab Half of the width of the slab Three-fourth of the width of the slab Two-third of the width of the slab Four-fifth of the width of the slab Half of the width of the slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm², the share stirrups are provided for a distance ‘x’ from either end where, ‘x’ is 200 cm 100 cm 50 cm 150 cm 200 cm 100 cm 50 cm 150 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to load factor method, the permissible load ‘W’ on a short column reinforced with longitudinal bars and lateral stirrups, is None of these Stress in steel × area of steel Stress in concrete × area of concrete Stress in concrete × area of concrete + Stress in steel × area of steel None of these Stress in steel × area of steel Stress in concrete × area of concrete Stress in concrete × area of concrete + Stress in steel × area of steel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
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