RCC Structures Design The percentage of minimum reinforcement of the gross sectional area in slabs, is 0.12 % 0.15 % 0.18 % 0.10 % 0.12 % 0.15 % 0.18 % 0.10 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The minimum stress ‘f’ on the beam subjected to a maximum bending moment ‘M’ is f = (P/A) - (M/6Z) f = (P/'- (Z/M) f = (A/P) - (M/Z) f = (P/A) - (M/Z) f = (P/A) - (M/6Z) f = (P/'- (Z/M) f = (A/P) - (M/Z) f = (P/A) - (M/Z) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pile of length ‘L’ carrying a uniformly distributed load ‘W’ per metre length is suspended at two points, the maximum, B.M. at the centre of the pile or at the points of suspension, is WL/8 WL²/24 WL²/16 WL²/47 WL/8 WL²/24 WL²/16 WL²/47 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For initial estimate for a beam design, the width is assumed 1/30th of span 1/15th of span 1/25th of span 1/20th of span 1/30th of span 1/15th of span 1/25th of span 1/20th of span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum dip of a parabolic tendon carrying tension P is h and the effective length of the pre-stressed beam is L, the upward uniform pressure will be 8hl/p 8hp/l² 8hp/l 8hl/p² 8hl/p 8hp/l² 8hp/l 8hl/p² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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