RCC Structures Design The percentage of minimum reinforcement of the gross sectional area in slabs, is 0.10 % 0.18 % 0.12 % 0.15 % 0.10 % 0.18 % 0.12 % 0.15 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The effective width of a column strip of a flat slab, is Diameter of the column Radius of the column Half the width of the panel One-fourth the width of the panel Diameter of the column Radius of the column Half the width of the panel One-fourth the width of the panel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Long and short spans of a two way slab are ly and lx and load on the slab acting on strips parallel to lx and ly be wx and wy respectively. According to Rankine Grashoff theory (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)² None of these (wx/wy) = (ly/lx)⁴ (wx/wy) = (ly/lx) (wx/wy) = (ly/lx)² None of these (wx/wy) = (ly/lx)⁴ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The Young's modulus of elasticity of steel, is 275 KN/mm² 250 KN/mm² 150 KN/mm² 200 KN/mm² 275 KN/mm² 250 KN/mm² 150 KN/mm² 200 KN/mm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member Possesses internal stresses Is made of reinforced concrete Is stressed after casting Is made of concrete Possesses internal stresses Is made of reinforced concrete Is stressed after casting Is made of concrete ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) ANSWER DOWNLOAD EXAMIANS APP
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