RCC Structures Design The percentage of minimum reinforcement of the gross sectional area in slabs, is 0.10 % 0.15 % 0.12 % 0.18 % 0.10 % 0.15 % 0.12 % 0.18 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The minimum stress ‘f’ on the beam subjected to a maximum bending moment ‘M’ is f = (A/P) - (M/Z) f = (P/'- (Z/M) f = (P/A) - (M/Z) f = (P/A) - (M/6Z) f = (A/P) - (M/Z) f = (P/'- (Z/M) f = (P/A) - (M/Z) f = (P/A) - (M/6Z) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The weight of a foundation is assumed as 12% of wall weight 10% of wall weight 5% of wall weight 7% of wall weight 12% of wall weight 10% of wall weight 5% of wall weight 7% of wall weight ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The spacing of transverse reinforcement of column is decided by the following consideration. The least lateral dimension of the column Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column All listed here Forty-eight times the diameter of transverse reinforcement The least lateral dimension of the column Sixteen times the diameter of the smallest longitudinal reinforcing rods in the column All listed here Forty-eight times the diameter of transverse reinforcement ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. column of 30 cm diameter is reinforced with 6 bars 12 mm φ placed symmetrically along the circumference. If it carries a load of 40,000 kg axially, the stress is 49.9 kg/cm² 175 kg/cm² 100 kg/cm² 250 kg/cm² 49.9 kg/cm² 175 kg/cm² 100 kg/cm² 250 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
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