RCC Structures Design Piles are usually driven by Single acting steam hammer Drop hammer Diesel operated hammer All listed here Single acting steam hammer Drop hammer Diesel operated hammer All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a combined footing for two columns carrying unequal loads, the maximum hogging bending moment occurs at A point of zero shear force Less loaded column More loaded column A point of the maximum shear force A point of zero shear force Less loaded column More loaded column A point of the maximum shear force ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A part of the slab may be considered as the flange of the T-beam if Flange has adequate reinforcement transverse to beam It is built integrally with the beam It is effectively bonded together with the beam All of the listed here Flange has adequate reinforcement transverse to beam It is built integrally with the beam It is effectively bonded together with the beam All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If a rectangular pre-stressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be 10 cm 20 cm 5 cm 15 cm 10 cm 20 cm 5 cm 15 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond length is given by (π/4). (ft .d/fb) ft .d/4fb (π/4). (ft .d3/fb) π ft .d²/fb (π/4). (ft .d/fb) ft .d/4fb (π/4). (ft .d3/fb) π ft .d²/fb ANSWER DOWNLOAD EXAMIANS APP
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