RCC Structures Design If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by (5/6) (r²/1 + r³) M (5/6) (r²/1 + r⁴) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r²/1 + r⁴) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r²) M ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If jd is the lever arm and ΣO is the total perimeter of reinforcement of an R.C.C. beam, the bond stress at the section having Q shear force, is Q/3jdƩO 2 × Q/jdƩO Q/jdƩO Q/2jdƩO Q/3jdƩO 2 × Q/jdƩO Q/jdƩO Q/2jdƩO ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If T and R are tread and rise respectively of a stair, then R + 2T= 30 2R + T = 30 2R + T = 60 R + 2T = 60 R + 2T= 30 2R + T = 30 2R + T = 60 R + 2T = 60 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Minimum spacing between horizontal parallel reinforcement of the same size should not be less than 3.5 diameters 2.5 diameters 3 diameters One diameter 3.5 diameters 2.5 diameters 3 diameters One diameter ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The amount of reinforcement for main bars in a slab, is based upon Minimum bending moment Maximum shear force Maximum bending moment Minimum shear force Minimum bending moment Maximum shear force Maximum bending moment Minimum shear force ANSWER DOWNLOAD EXAMIANS APP
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