RCC Structures Design The amount of reinforcement for main bars in a slab, is based upon Maximum bending moment Minimum bending moment Minimum shear force Maximum shear force Maximum bending moment Minimum bending moment Minimum shear force Maximum shear force ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If P kg/m² is the upward pressure on the slab of a plain concrete footing whose projection on either side of the wall is a cm, the depth of foundation D is given by D = 0.775 Pa D = 0.00775 aP D = 0.07775 aP D = 0.0775 aP D = 0.775 Pa D = 0.00775 aP D = 0.07775 aP D = 0.0775 aP ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a combined footing if shear stress exceeds 5 kg/cm², the nominal stirrups provided are: 12 legged 10 legged 6 legged 8 legged 12 legged 10 legged 6 legged 8 legged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)² w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to the steel beam theory of doubly reinforced beams All of the listed here Stress in tension steel equals the stress in compression steel Compression is resisted by compression steel Tension is resisted by tension steel All of the listed here Stress in tension steel equals the stress in compression steel Compression is resisted by compression steel Tension is resisted by tension steel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum bending moment of a simply supported slab is M Kg.cm, the effective depth of the slab is (where Q is M.R. factor) √(M/100Q) M/100Q M/10√Q √(M/Q) √(M/100Q) M/100Q M/10√Q √(M/Q) ANSWER DOWNLOAD EXAMIANS APP
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