RCC Structures Design In a beam the local bond stress Sb, is equal to Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Leaver arm/(Shear force × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (m + c)/t = n/(d + n) mc/t = (d - n)/t mc/t = n/(d - n) (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = (d - n)/t mc/t = n/(d - n) (t + c)/n = (d + n)/n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A continuous beam shall be deemed to be a deep beam if the ratio of effective span to overall depth, is Less than 2 2 2.5 Less than 2.5 Less than 2 2 2.5 Less than 2.5 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p1 is the vertical intensity of pressure at a depth h on a block of earth weighing w per unit volume and the angle of repose φ, the lateral intensity of pressure p2 is w (1 - cos φ)/h (1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) wh (1 - sin φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) wh (1 - sin φ)/(1 + sin φ) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm², the share stirrups are provided for a distance ‘x’ from either end where, ‘x’ is 100 cm 150 cm 200 cm 50 cm 100 cm 150 cm 200 cm 50 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond length is given by π ft .d²/fb (π/4). (ft .d3/fb) (π/4). (ft .d/fb) ft .d/4fb π ft .d²/fb (π/4). (ft .d3/fb) (π/4). (ft .d/fb) ft .d/4fb ANSWER DOWNLOAD EXAMIANS APP
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