RCC Structures Design In a beam the local bond stress Sb, is equal to Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design On an absolutely rigid foundation base, the pressure will Be more at the edges of the foundation Be zero at the centre of the foundation Not be uniform Be uniform Be more at the edges of the foundation Be zero at the centre of the foundation Not be uniform Be uniform ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to the steel beam theory of doubly reinforced beams Tension is resisted by tension steel Compression is resisted by compression steel Stress in tension steel equals the stress in compression steel All of the listed here Tension is resisted by tension steel Compression is resisted by compression steel Stress in tension steel equals the stress in compression steel All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to load factor method, the permissible load ‘W’ on a short column reinforced with longitudinal bars and lateral stirrups, is None of these Stress in concrete × area of concrete + Stress in steel × area of steel Stress in concrete × area of concrete Stress in steel × area of steel None of these Stress in concrete × area of concrete + Stress in steel × area of steel Stress in concrete × area of concrete Stress in steel × area of steel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 1343, total shrinkage for a pre-tensioned beam, is 3.0 × 10⁻⁵ 3.0 × 10⁻² 3.5 × 10⁻⁵ 3.0 × 10⁻³ 3.0 × 10⁻⁵ 3.0 × 10⁻² 3.5 × 10⁻⁵ 3.0 × 10⁻³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/2Sb l = dt/3Sb l = dt/4Sb l = dt/Sb l = dt/2Sb l = dt/3Sb l = dt/4Sb l = dt/Sb ANSWER DOWNLOAD EXAMIANS APP
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