RCC Structures Design The zone in which transverse bending is likely to occur may be obtained by drawing a line from the faces of the column making an angle θ° with horizontal where θ° is 30° 45° None of these 60° 30° 45° None of these 60° ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p1 is the vertical intensity of pressure at a depth h on a block of earth weighing w per unit volume and the angle of repose φ, the lateral intensity of pressure p2 is wh (1 - sin φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) wh (1 - sin φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - cos φ)/(1 + sin φ) wh (1 - tan φ)/(1 + tan φ) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the loading on a pre-stressed rectangular beam, is uniformly distributed, the tendon to be provided should be. Straight above centroidal axis Parabolic with convexity upward Straight below centroidal axis Parabolic with convexity downward Straight above centroidal axis Parabolic with convexity upward Straight below centroidal axis Parabolic with convexity downward ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. beam of 25 cm width and 50 cm effective depth has a clear span of 6 meters and carries a U.D.L. of 3000 kg/m inclusive of its self weight. If the lever arm constant for the section is 0.865, the maximum intensity of shear stress, is 21.5 kg/cm² 8.3 kg/cm² 7.6 kg/cm² 21.5 kg/cm² 21.5 kg/cm² 8.3 kg/cm² 7.6 kg/cm² 21.5 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b - a)²/4 ANSWER DOWNLOAD EXAMIANS APP
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