RCC Structures Design The neutral axis of a T-beam exists All listed here At the bottom edge of the slab Below the slab Within the flange All listed here At the bottom edge of the slab Below the slab Within the flange ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by (5/6) (r²/1 + r³) M (5/6) (r²/1 + r²) M (5/6) (r²/1 + r⁴) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r²/1 + r²) M (5/6) (r²/1 + r⁴) M (5/6) (r/1 + r²) M ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a singly reinforced beam Compression is borne entirely by concrete Steel possesses initial stresses when embedded in concrete Plane sections transverse to the centre line of the beam before bending remain plane after bending Elastic moduli for concrete and steel have different values within the limits of deformation of the beam Compression is borne entirely by concrete Steel possesses initial stresses when embedded in concrete Plane sections transverse to the centre line of the beam before bending remain plane after bending Elastic moduli for concrete and steel have different values within the limits of deformation of the beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Minimum spacing between horizontal parallel reinforcement of different sizes, should not be less than Twice the diameter of thinner bar One diameter of thinner bar One diameter of thicker bar None of these Twice the diameter of thinner bar One diameter of thinner bar One diameter of thicker bar None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a beam the local bond stress Sb, is equal to Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) Leaver arm/(Bending moment × Total perimeter of reinforcement) Shear force/(Leaver arm × Total perimeter of reinforcement) Total perimeter of reinforcement/(Leaver arm × Shear force) Leaver arm/(Shear force × Total perimeter of reinforcement) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The diameter of the column head support a flat slab, is generally kept 0.25 times the diameter of the column 0.25 times the span length 5.0 cm larger than the diameter of the column 4.0 cm larger than the diameter of the column 0.25 times the diameter of the column 0.25 times the span length 5.0 cm larger than the diameter of the column 4.0 cm larger than the diameter of the column ANSWER DOWNLOAD EXAMIANS APP
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