RCC Structures Design If the diameter of the main reinforcement in a slab is 16 mm, the concrete cover to main bars is 12 mm 16 mm 14 mm 10 mm 12 mm 16 mm 14 mm 10 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In the zone of R.C.C. beam where shear stress is less than 5 kg/cm², nominal reinforcement is provided at a pitch of One-half lever arm of the section One and half lever arm of the section Lever arm of the section One-third lever arm of the section One-half lever arm of the section One and half lever arm of the section Lever arm of the section One-third lever arm of the section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a singly reinforced beam, the effective depth is measured from its compression edge to Tensile edge Tensile reinforcement Longitudinal central axis Neutral axis of the beam Tensile edge Tensile reinforcement Longitudinal central axis Neutral axis of the beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Pick up the true statement from the following: Plain ceiling provides the best property diffusing light In the absence of beams, it is easier to paint In the absence of beams, it is easier to install piping All listed here Plain ceiling provides the best property diffusing light In the absence of beams, it is easier to paint In the absence of beams, it is easier to install piping All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The thickness of base slab of a retaining wall generally provided, is Width of the stem at the bottom One-third of the width of the stem at the bottom One half of the width of the stem at the bottom One fourth of the width of the steam at the bottom Width of the stem at the bottom One-third of the width of the stem at the bottom One half of the width of the stem at the bottom One fourth of the width of the steam at the bottom ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ ANSWER DOWNLOAD EXAMIANS APP
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