RCC Structures Design If the diameter of the main reinforcement in a slab is 16 mm, the concrete cover to main bars is 12 mm 14 mm 16 mm 10 mm 12 mm 14 mm 16 mm 10 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a combined footing if shear stress exceeds 5 kg/cm², the nominal stirrups provided are: 12 legged 6 legged 10 legged 8 legged 12 legged 6 legged 10 legged 8 legged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The diameter of the column head support a flat slab, is generally kept 0.25 times the diameter of the column 0.25 times the span length 5.0 cm larger than the diameter of the column 4.0 cm larger than the diameter of the column 0.25 times the diameter of the column 0.25 times the span length 5.0 cm larger than the diameter of the column 4.0 cm larger than the diameter of the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of R.C.C. simply supported beams carrying U.D.L. is based on the resultant B.M. at Mid span Supports Every section Quarter span Mid span Supports Every section Quarter span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/4a²bq D = W (a - b)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4abq D = W (a² - b²)/4a²bq D = W (a - b)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4abq ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)² w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)² w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)⁴ ANSWER DOWNLOAD EXAMIANS APP
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