RCC Structures Design With usual notations the depth of the neutral axis of a balanced section, is given by t/mc = (d + n)/n mc/t = n/(d - n) t/mc = (d - n)/n mc/t = (d - n)/n t/mc = (d + n)/n mc/t = n/(d - n) t/mc = (d - n)/n mc/t = (d - n)/n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the permissible compressive and tensile stresses in a singly reinforced beam are 50 kg/cm² and 1400 kg/cm² respectively and the modular ratio is 18, the percentage area At of the steel required for an economic section, is 0.796 % 0.496 % 0.596 % 0.696 % 0.796 % 0.496 % 0.596 % 0.696 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to the tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The maximum stress ‘f’ in the beam, subjected to a maximum bending moment ‘M’, is f = (P/'+ (Z/M) f = (P/A) + (M/Z) f = (P/A) + (M/6Z) f = (A/P) + (M/Z) f = (P/'+ (Z/M) f = (P/A) + (M/Z) f = (P/A) + (M/6Z) f = (A/P) + (M/Z) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In favourable circumstances a 15 cm concrete cube after 28 days, attains a maximum crushing strength 100 kg/cm² 200 kg/cm² 400 kg/cm² 300 kg/cm² 100 kg/cm² 200 kg/cm² 400 kg/cm² 300 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of R.C.C. cantilever beams, is based on the resultant force at Free end Mid span Fixed end Mid span and fixed support Free end Mid span Fixed end Mid span and fixed support ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to the steel beam theory of doubly reinforced beams Compression is resisted by compression steel All of the listed here Tension is resisted by tension steel Stress in tension steel equals the stress in compression steel Compression is resisted by compression steel All of the listed here Tension is resisted by tension steel Stress in tension steel equals the stress in compression steel ANSWER DOWNLOAD EXAMIANS APP
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