RCC Structures Design With usual notations the depth of the neutral axis of a balanced section, is given by mc/t = (d - n)/n t/mc = (d + n)/n mc/t = n/(d - n) t/mc = (d - n)/n mc/t = (d - n)/n t/mc = (d + n)/n mc/t = n/(d - n) t/mc = (d - n)/n ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a cantilever retaining wall without a heel slab All listed here Width of the base slab is kept 0.7 time the total height of the wall Base slab is made 10 cm thicker than the stem Thickness of the stem is kept same throughout All listed here Width of the base slab is kept 0.7 time the total height of the wall Base slab is made 10 cm thicker than the stem Thickness of the stem is kept same throughout ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 15 cm² 16 cm² 14 cm² 17 cm² 15 cm² 16 cm² 14 cm² 17 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the ratio of long and short spans of a two way slab with corners held down is r, the actual reduction of B.M. is given by (5/6) (r²/1 + r²) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r²/1 + r⁴) M (5/6) (r²/1 + r²) M (5/6) (r/1 + r²) M (5/6) (r²/1 + r³) M (5/6) (r²/1 + r⁴) M ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because Removal of cracks in the members due to shrinkage All listed here Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress Removal of cracks in the members due to shrinkage All listed here Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design High strength concrete is used in pre-stressed member To provide high bond stresses To overcome bursting stresses at the ends All listed here To overcome high bearing stresses developed at the ends To provide high bond stresses To overcome bursting stresses at the ends All listed here To overcome high bearing stresses developed at the ends ANSWER DOWNLOAD EXAMIANS APP
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